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Proof step 56 from proof range-eq-splice-less (previous step)

n3 < m0, n3 < m1, # ar0 < n0 + m1, # ar0 < n0 + m0, n2 + m1 ≤ # ar2, n + m0 ≤ # ar, m1 ≤ m0, n1 ≤ n0, ∀ n3. n3 < m1 → ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m1), n0, m1)[n1 + n3] ⊦ ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m0), n0, m0)[n1 + n3], m0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 57:
n3 < m0, n3 < m1, # ar0 < n0 + m1, # ar0 < n0 + m0, n2 + m1 ≤ # ar2, n + m0 ≤ # ar, m1 ≤ m0, n1 ≤ n0, ∀ n3. n3 < m1 → ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m1), n0, m1)[n1 + n3] ⊦ ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m0), n0, m0)[n1 + n3]

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)