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Proof step 4 from proof subarray-append-elim-left (previous step)

n0 = n1 + # ar0, n0 + m ≤ # ar0 + # ar1, # ar0 ≤ n0 ⊦ subarray(ar0 + ar1, n0, m) = subarray(ar1, n1, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n1 + m ≤ # ar1 ⊦ subarray(ar0 + ar1, n1 + # ar0, m) = subarray(ar1, n1, m)

Rule argument

Additional information

Used simplifier rules: ⊦ m + n ≤ m + n0 ↔ n ≤ n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)