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Proof step 5 from proof subarray-append-elim-left (previous step)

n1 + m ≤ # ar1 ⊦ subarray(ar0 + ar1, n1 + # ar0, m) = subarray(ar1, n1, m)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ subarray(ar, m, n) = copy(ar, m, mkarray(n), 0, n)
Proof step 7:
n1 + m ≤ # ar1 ⊦ copy(ar0 + ar1, n1 + # ar0, mkarray(m), 0, m) = subarray(ar1, n1, m)

Rule argument

spec: array-copy name: Subarray seq: ⊦ subarray(ar, m, n) = copy(ar, m, mkarray(n), 0, n) subst: [n, m, ar] → [m, n1 + # ar0, ar0 + ar1] flags: <all paths>

Additional information

Used terms: m, n1 + # ar0, ar0 + ar1