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Theorem subarray-elim

⊦ n + m ≤ # ar → (ar1 = subarray(ar, n, m) ↔ (∃ ar0, ar2. ar = ar0 + ar1 + ar2 ∧ # ar0 = n ∧ # ar1 = m))

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes

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Infos about the proof

Proved?: Yes
Interactions: 4
Proof steps: 10
Used lemmas: subarray-append-elim-left0, subarray-elim-right, append-len, append-prefix-left, append-a, subarray-append-consec0,
Used spec theorems:
- Used simplifier rules: