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Proof step 27 from proof emptystream-cancel (previous step)

#(σ⊥ to n) = ⌜n⌝ ⊦ # σ⊥ = ∞, (σ⊥ to n) + σ⊥ = σ⊥

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
#(σ⊥ to n) = ⌜n⌝ ⊦ # σ⊥ = ∞, σ⊥ to n = []

Rule argument

Additional information

Used simplifier rules: append-assoc: ⊦ (σ0 + σ3) + σ4 = σ0 + σ3 + σ4; from specification stream[buffer-inf]%finp(σ1) ⊦ σ2 + σ1 = σ1 ↔ σ2 = []; (s)% ⊦ ¬ finp(σ0) → # σ0 = ∞; (s)