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Proof step 28 from proof emptystream-cancel (previous step)

#(σ⊥ to n) = ⌜n⌝ ⊦ # σ⊥ = ∞, σ⊥ to n = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 29:
⊦ σ⊥ = ⌜λ n. zero⌝

Rule argument

spec: <toplevel> name: emptystream seq: ⊦ σ⊥ = ⌜λ n. zero⌝ subst: flags: <all paths>

Additional information

Used simplifier rules: ⊦ ⌜nf0⌝ to n = ⌜nf0 to n⌝ ; (s)% ⊦ # ⌜nf0 to n⌝ = ⌜n⌝ ; (s)% ⊦ ⌜m⌝ = ⌜m0⌝ ↔ m = m0; (s)% ⊦ ⌜dx⌝ = [] ↔ dx = []; (s)% ⊦ nf0 to n = [] ↔ n = 0; (s)% ⊦ # ⌜nf0⌝ = ∞; (s) Used terms: