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Proof step 7 from proof subarray-append-mkempbuf-from (previous step)

n < n2, n < n1 + # buf, n2 ≤ n1 + # buf ⊦ (n < n1 ⊃ mkempbuf(n0 + n1)[n0 + n];buf[n - n1]) = (mkempbuf(n1) + buf)[n]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ n < # buf + # buf0 → (buf + buf0)[n] = (n < # buf ⊃ buf[n];buf0[n - # buf])
Proof step 9:
n < n1 + # buf, n < n2, n < # mkempbuf(n1) + # buf, n2 ≤ n1 + # buf ⊦ (n < n1 ⊃ mkempbuf(n0 + n1)[n0 + n];buf[n - n1]) = (n < # mkempbuf(n1) ⊃ mkempbuf(n1)[n];buf[n - # mkempbuf(n1)])

Rule argument

spec: array-splice, inst: buffer name: append-at seq: ⊦ n < # buf + # buf0 → (buf + buf0)[n] = (n < # buf ⊃ buf[n];buf0[n - # buf]) subst: [n, buf0, buf] → [n, buf, mkempbuf(n1)] flags: <all paths>

Additional information

Used simplifier rules: ⊦ # mkempbuf(n) = n; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → (n ≤ m ↔ false); (s) Used terms: n, buf, mkempbuf(n1)