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Proof step 9 from proof subarray-append-mkempbuf-from (previous step)

n < n1 + # buf, n < n2, n < # mkempbuf(n1) + # buf, n2 ≤ n1 + # buf ⊦ (n < n1 ⊃ mkempbuf(n0 + n1)[n0 + n];buf[n - n1]) = (n < # mkempbuf(n1) ⊃ mkempbuf(n1)[n];buf[n - # mkempbuf(n1)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
n < n2, n < n1 + # buf, n2 ≤ n1 + # buf ⊦ (n < n1 ⊃ mkempbuf(n0 + n1)[n0 + n];buf[n - n1]) = (n < n1 ⊃ empty;buf[n - n1])

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → mkempbuf(n)[m] = empty; (s)% ⊦ # mkempbuf(n) = n; (s)