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Proof step 5 from proof datasize-is-smaller-help (previous step)

n0 +1 < datasize(buf, n0 +1), ∀ buf. ¬ n0 < datasize(buf, n0) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ datasize(buf, n + 1) = (buf[n] = empty ⊃ datasize(buf, n);n + 1)
Proof step 7:
n0 + 1 < (buf[n0] = empty ⊃ datasize(buf, n0);n0 + 1), ∀ buf. ¬ n0 < datasize(buf, n0) ⊦

Rule argument

Additional information

Used simplifier rules: datasize-rec: ⊦ datasize(buf, n + 1) = (buf[n] = empty ⊃ datasize(buf, n);n + 1);% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m +1 = m + 1; (s)