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Proof step 7 from proof datasize-is-smaller-help (previous step)

n0 + 1 < (buf[n0] = empty ⊃ datasize(buf, n0);n0 + 1), ∀ buf. ¬ n0 < datasize(buf, n0) ⊦

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 8:
buf[n0] = empty, n0 + 1 < datasize(buf, n0), ∀ buf. ¬ n0 < datasize(buf, n0) ⊦

Rule argument

pos: left 1

Additional information

Used simplifier rules: ⊦ m + n < m + n0 ↔ n < n0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic