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Proof step 12 from proof isprefix-add-prefixn-size (previous step)

x0 + z = x1 + x2, # x1 + n < # x0 ⊦ x0 = [], n ≤ # x2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
x0 + z = x1 + x2, # x2 < n, # x1 + n < # x0 ⊦ x0 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)