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Proof step 7 from proof isprefix-add-prefixn-size (previous step)

x0 + z = x1 + (n ≤ # x2 ⊃ firstn(n, x2);x2), # x1 + n < # x0 ⊦ x0 = []

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 8:
x0 + z = x1 + firstn(n, x2), # x1 + n < # x0, n ≤ # x2 ⊦ x0 = []
Proof step 12:
x0 + z = x1 + x2, # x1 + n < # x0 ⊦ x0 = [], n ≤ # x2

Rule argument

pos: left 1

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