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Theorem isprefix-prefixn

⊦ x0 ⊑ x1 → (x0 = prefixn(n, x1) ↔ n = # x0 ∨ n > # x0 ∧ x0 = x1)

Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 0
Proof steps: 3
Used lemmas: prefixn,
Used spec theorems:
- Used simplifier rules: