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Proof step 1 from proof max-comm (conclusion)

⊦ max(n0, n1) = max(n1, n0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ max(n, m) = (n < m ⊃ m;n)
Proof step 3:
⊦ (n0 < n1 ⊃ n1;n0) = (n1 < n0 ⊃ n0;n1)

Rule argument

Additional information

Used simplifier rules: max: ⊦ max(n, m) = (n < m ⊃ m;n);