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Proof step 3 from proof max-comm (previous step)

⊦ (n0 < n1 ⊃ n1;n0) = (n1 < n0 ⊃ n0;n1)

User applied rule case distinction

And obtained the following new goals

Proof step 4:
⊦ n0 = (n1 < n0 ⊃ n0;n1), n0 < n1

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m; (s)