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Proof step 4 from proof inv-recover (previous step)

avol = avol0, ebm-vol-inv(avol1), avol1 ⊆ avol0 ⊦ ⟪fail_or_success#(; ; err); if err ≠ ESUCCESS then avol := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol))

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 5:
avol = avol0, ebm-vol-inv(avol1), avol1 ⊆ avol0 ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err ≠ ESUCCESS then avol := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol))

Rule argument

pos: right 1

Additional information

Used simplifier rules: fail_or_success#(; ; ERR) {choose ERR0 with ⌊ERR0⌋ ∨ ERR0 = ESUCCESS in ERR := ERR0};