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Proof step 5 from proof inv-recover (previous step)

avol = avol0, ebm-vol-inv(avol1), avol1 ⊆ avol0 ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err ≠ ESUCCESS then avol := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol))

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 6:
avol = avol0, ebm-vol-inv(avol1), avol1 ⊆ avol0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err ≠ ESUCCESS then avol := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol))
Proof step 10:
avol = avol0, ebm-vol-inv(avol1), avol1 ⊆ avol0 ⊦ ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 5 from proof inv-recover (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information