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Proof step 6 from proof inv-recover (previous step)

avol = avol0, ebm-vol-inv(avol1), avol1 ⊆ avol0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err ≠ ESUCCESS then avol := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 7:
avol = avol0, err = err0, ebm-vol-inv(avol1), avol1 ⊆ avol0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err ≠ ESUCCESS then avol := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol))

Proof step 6 from proof inv-recover (previous step)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

Additional information