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Proof step 11 from proof new-append (previous step)

∀ ax1, fs. new(ax + ax1, fs) ↔ new(ax, fs) ∧ new(ax1, fs) ⊦ new(ax + ax1, fs) ↔ new(ax, fs) ∧ new(ax1, fs), new(ax + ax1, fs), adr ∈ fs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information