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Proof step 12 from proof new-append (previous step)

new(ax, fs), new(ax1, fs), ∀ ax1, fs. new(ax + ax1, fs) ↔ new(ax, fs) ∧ new(ax1, fs) ⊦ new(ax + ax1, fs), adr ∈ fs

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: ax1, fs

Additional information

Used terms: ax1, fs