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Proof step 5 from proof read-split (previous step)

fs[adr] ' + fs[ax0] = ndx0 + ndx1, fs[adr] ∈ ndx0, ∀ fs, ndx0, ndx1. fs[ax0] = ndx0 + ndx1 → (∃ ax2, ax1. ax0 = ax2 + ax1 ∧ fs[ax2] = ndx0 ∧ fs[ax1] = ndx1), fs[adr] ∈ ndx0 ∨ fs[adr] ∈ ndx1 ⊦ ∃ ax, ax1. adr ' + ax0 = ax + ax1 ∧ fs[ax] = ndx0 ∧ fs[ax1] = ndx1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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