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Proof step 10 from proof down-except-refsize (previous step)

gstore0 ↓[n] = groupblock(gndx0, lax0, m0), gstore1 ↓[n] = groupblock(gndx, lax, m), ∀ n. (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist ⊦ (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gndx = gndx0 ∧ lax = lax0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ n ∈ gstore → gstore ↓[n] = gstore[n] ↓
Proof step 12:
gstore1 ↓[n] = groupblock(gndx, lax, m), gstore0 ↓[n] = groupblock(gndx0, lax0, m0), ∀ n. (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist ⊦ n ∈ gstore0, (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gndx = gndx0 ∧ lax = lax0
Proof step 20:
gstore1 ↓[n] = groupblock(gndx, lax, m), gstore0[n] ↓ = groupblock(gndx0, lax0, m0), n ∈ gstore0, ∀ n. (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist ⊦ (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gndx = gndx0 ∧ lax = lax0

Rule argument

spec: <toplevel> name: down-store-at seq: ⊦ n ∈ gstore → gstore ↓[n] = gstore[n] ↓ subst: [n, gstore] → [n, gstore0] flags: <all paths>

Additional information

Used terms: n, gstore0