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Proof step 8 from proof down-except-refsize (previous step)

gstore1 ↓[n] = groupblock(gndx, lax, m), gstore0 ↓[n] = groupblock(gndx0, lax0, m0), gstore1 =○refsize gstore0 ⊦ (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gndx = gndx0 ∧ lax = lax0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ gstore =○refsize gstore0 ↔ (∀ n. (n ∈ gstore ↔ n ∈ gstore0) ∧ gstore[n].gndlist = gstore0[n].gndlist ∧ gstore[n].ladrlist = gstore0[n].ladrlist)
Proof step 10:
gstore0 ↓[n] = groupblock(gndx0, lax0, m0), gstore1 ↓[n] = groupblock(gndx, lax, m), ∀ n. (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist ⊦ (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gndx = gndx0 ∧ lax = lax0

Rule argument

spec: ablock-store-inv, inst: group-store name: except-refsize-eq seq: ⊦ gstore =○refsize gstore0 ↔ (∀ n. (n ∈ gstore ↔ n ∈ gstore0) ∧ gstore[n].gndlist = gstore0[n].gndlist ∧ gstore[n].ladrlist = gstore0[n].ladrlist) subst: [gstore0, gstore] → [gstore0, gstore1] flags: <all paths>

Additional information

Used terms: gstore0, gstore1