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Proof step 2 from proof gstore-dom-eq-hole (previous step)

gstore0 \ {n} = gstore1 \ {n} , dom gstore0 = dom gstore1, n ∈ gstore0 ⊦ ∃ gblock. gstore1 = gstore0[n, gblock]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
gstore0 \ (∅ ++ n) = gstore1 \ (∅ ++ n), dom gstore0 = dom gstore1, n ∈ gstore0 ⊦ ∃ gblock. gstore1 = gstore0[n, gblock]

Rule argument

Additional information

Used simplifier rules: ⊦ {n} = ∅ ++ n; (s)