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Proof step 3 from proof gstore-dom-eq-hole (previous step)

gstore0 \ (∅ ++ n) = gstore1 \ (∅ ++ n), dom gstore0 = dom gstore1, n ∈ gstore0 ⊦ ∃ gblock. gstore1 = gstore0[n, gblock]

User applied rule exists right

And obtained the following new goals

Proof step 4:
gstore0 \ (∅ ++ n) = gstore1 \ (∅ ++ n), dom gstore0 = dom gstore1, n ∈ gstore0 ⊦ gstore1 = gstore0[n, gstore1[n]]

Rule argument

pos: right 1 terms: gstore1[n] abort: F discard: T computed: F

Additional information

Used terms: gstore1[n]