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Proof step 5 from proof jnlhd-notin-ginval (previous step)

nx.last ∈ ginval, ∀ n. n ∈ elems nx ∩ ginval ↔ n ∈ ∅ ⊦ # ginval = 0, ginval = ∅, nx = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
nx.last ∈ ginval, ∀ n. ¬ n ∈ elems nx ∩ ginval ⊦ # ginval = 0, ginval = ∅, nx = []

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ n ∈ ∅; (s)