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Proof step 6 from proof jnlhd-notin-ginval (previous step)

nx.last ∈ ginval, ∀ n. ¬ n ∈ elems nx ∩ ginval ⊦ # ginval = 0, ginval = ∅, nx = []

User applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: nx.last abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ n ∈ ns ∩ ns0 ↔ n ∈ ns ∧ n ∈ ns0; (ws)% ⊦ n ∈ elems nx ↔ n ∈ nx; (s)% ⊦ nx.last ∈ nx ↔ nx ≠ []; (s)%int-a: ⊦ (ns ∩ ns0) ∩ ns1 = ns ∩ ns0 ∩ ns1; from specification set-union[nat-set]%int-c: ⊦ ns ∩ ns0 = ns0 ∩ ns; from specification set-union[nat-set] Used terms: nx.last