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Proof step 11 from proof restr-add-notin (previous step)

n0 = n ∨ n0 ∈ ns ∧ ¬ n0 ∈ dom gstore ⊦ n ∈ gstore, (n0 = n ∨ n0 ∈ ns) ∧ ¬ n0 ∈ gstore

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
n0 = n ∨ n0 ∈ ns ∧ ¬ n0 ∈ gstore ⊦ n ∈ gstore, (n0 = n ∨ n0 ∈ ns) ∧ ¬ n0 ∈ gstore

Rule argument

Additional information

Used simplifier rules: ⊦ n ∈ dom gstore ↔ n ∈ gstore; (s)