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Proof step 12 from proof restr-add-notin (
previous step
)
n0 = n ∨ n0 ∈ ns ∧ ¬ n0 ∈ gstore ⊦ n ∈ gstore, (n0 = n ∨ n0 ∈ ns) ∧ ¬ n0 ∈ gstore
User applied rule case distinction
And closed the goal!
Rule argument
pos: right 2
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