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Proof step 12 from proof lebs-rem-subseteq (previous step)

@(m, m0, m1) ∈ ri \ ks, (∃ adr. adr.lnum = m ∧ adr ∈ ri) → m ∈ ns ⊦ m ∈ ns, (ri \ ks).lebs ⊆ ri.lebs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information