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Proof step 13 from proof lebs-rem-subseteq (previous step)

@(m, m0, m1) ∈ ri \ ks ⊦ m ∈ ns, (ri \ ks).lebs ⊆ ri.lebs, ∃ adr. adr.lnum = m ∧ adr ∈ ri

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: @(m, m0, m1)

Additional information

Used simplifier rules: in-rem-keys-in-data: ⊦ adr ∈ ri \ ks → adr ∈ ri;% ⊦ @(m, m0, m1).lnum = m; (s) Used terms: @(m, m0, m1)