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Theorem nds-eq-one

⊦ gndx.nds = nd ' ↔ (∃ gnd. gndx = gnd ' ∧ gnd.nd = nd)

Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by: nds-one,
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 0
Proof steps: 6
Used lemmas: nds-eq-empty, nds-rec, nds-base,
Used spec theorems:
- Used simplifier rules:
  - list/node-list/e
  - list/group-store/e
  - list/node-list/c
  - list/group-store/c
  - groupnode/elim
  - list/group-store/c-03
  - list/group-store/a
  - list/node-list/app
  - list/node-list/a
  - groupnode/sel
  - list/node-list/c-04
  - list/node-list/c-03