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Proof step 19 from proof referenced-adrs-lookup-keys-nodups (
previous step
)
⊦ referenced-adrs(ax, ri) = ax0 + ax1 ↔ (∃ ax2, ax3. ax = ax2 + ax3 ∧ referenced-adrs(ax2, ri) = ax0 ∧ referenced-adrs(ax3, ri) = ax1)
Lemma
referenced-adrs-split