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Theorem referenced-adrs-split

⊦ referenced-adrs(ax, ri) = ax0 + ax1 ↔ (∃ ax2, ax3. ax = ax2 + ax3 ∧ referenced-adrs(ax2, ri) = ax0 ∧ referenced-adrs(ax3, ri) = ax1)

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by: referenced-adrs-lookup-keys-nodups,
Used by units in proved state: gjournal-refine,
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 6
Proof steps: 18
Used lemmas: referenced-adrs-rec, referenced-adrs-base, referenced-adrs-app,
Used spec theorems:
- Used simplifier rules:
  - list/address-list-set/app-01
  - list/address-list-set/app-02
  - list/address-list-set/in-append
  - list/address-list-set/in-14
  - list/address-list-set/in-empty
  - list/address-list-set/in-rec
  - list/address-list-set/c-06
  - list/address-list-set/c
  - list/address-list-set/app-08
  - list/address-list-set/a
  - list/address-list-set/Nil