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Proof step 5 from proof referenced-adrs-lookup-keys-nodups (previous step)

dups(fs[(adr ∈ ri ⊃ adr ';[])].keys + fs[referenced-adrs(ax0, ri)].keys), ri-cons(ri, fs), ∀ fs0, ri0. ¬ dups(fs0[referenced-adrs(ax0, ri0)].keys) ∨ ¬ ri-cons(ri0, fs0) ⊦ dups(ax0), adr ∈ ax0

User applied rule all left

And obtained the following new goals

Proof step 6:
dups(fs[(adr ∈ ri ⊃ adr ';[])].keys + fs[referenced-adrs(ax0, ri)].keys), ri-cons(ri, fs), ¬ dups(fs[referenced-adrs(ax0, ri)].keys) ∨ ¬ ri-cons(ri, fs) ⊦ dups(ax0), adr ∈ ax0

Rule argument

pos: left 3 terms: fs, ri abort: F discard: T computed: T

Additional information

Used terms: fs, ri