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Proof step 6 from proof referenced-adrs-lookup-keys-nodups (previous step)

dups(fs[(adr ∈ ri ⊃ adr ';[])].keys + fs[referenced-adrs(ax0, ri)].keys), ri-cons(ri, fs), ¬ dups(fs[referenced-adrs(ax0, ri)].keys) ∨ ¬ ri-cons(ri, fs) ⊦ dups(ax0), adr ∈ ax0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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