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Proof step 10 from proof refsize-cons-crash (previous step)

(n ∈ nx ∨ ¬ n ∈ ginval ⊃ groupblock(gstore[n].gndlist, gstore[n].ladrlist, (n ∈ gstore0 ⊃ gstore0[n].ref-size;0));gstore0[n]) = groupblock(gndx, lax, m), dom gstore0 ∪ elems nx = dom gstore ∪ ginval, n ∈ crash(gstore, gstore0, ginval, nx), fi.lebs ⊆ dom gstore0, n ∈ gstore0 → gstore0[n].ref-size = (range fi | n).size ⊦ m = (range fi | n).size

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
(n ∈ nx ∨ ¬ n ∈ ginval ⊃ groupblock(gstore[n].gndlist, gstore[n].ladrlist, (n ∈ gstore0 ⊃ m0;0));gstore0[n]) = groupblock(gndx, lax, m), gstore0[n] = groupblock(gndx0, lax0, m0), dom gstore0 ∪ elems nx = dom gstore ∪ ginval, n ∈ crash(gstore, gstore0, ginval, nx), fi.lebs ⊆ dom gstore0, n ∈ gstore0 → m0 = (range fi | n).size ⊦ m = (range fi | n).size

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore0[n], gndx0, lax0, m0]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore0[n], gndx0, lax0, m0