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Proof step 9 from proof refsize-cons-crash (previous step)

(n ∈ nx ∨ ¬ n ∈ ginval ⊃ groupblock(gstore[n].gndlist, gstore[n].ladrlist, (n ∈ gstore0 ⊃ gstore0[n].ref-size;0));gstore0[n]) = groupblock(gndx, lax, m), dom gstore0 ∪ elems nx = dom gstore ∪ ginval, n ∈ crash(gstore, gstore0, ginval, nx), fi.lebs ⊆ dom gstore0, ∀ n. n ∈ gstore0 → gstore0[n].ref-size = (range fi | n).size ⊦ m = (range fi | n).size

User applied rule all left

And obtained the following new goals

Proof step 10:
(n ∈ nx ∨ ¬ n ∈ ginval ⊃ groupblock(gstore[n].gndlist, gstore[n].ladrlist, (n ∈ gstore0 ⊃ gstore0[n].ref-size;0));gstore0[n]) = groupblock(gndx, lax, m), dom gstore0 ∪ elems nx = dom gstore ∪ ginval, n ∈ crash(gstore, gstore0, ginval, nx), fi.lebs ⊆ dom gstore0, n ∈ gstore0 → gstore0[n].ref-size = (range fi | n).size ⊦ m = (range fi | n).size

Rule argument

pos: left 5 terms: n abort: F discard: T computed: T

Additional information

Used terms: n