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Proof step 6 from proof inv-isbad (previous step)

m < # pebs, mtd-cons(pebs) ⊦ ⟪fail_or_success#(; ; err); if err = ESUCCESS then isbad := pebs[m].bad else isbad := ?⟫ true

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 7:
m < # pebs, mtd-cons(pebs) ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then isbad := pebs[m].bad else isbad := ?⟫ true

Rule argument

pos: right 1

Additional information

Used simplifier rules: fail_or_success#(; ; ERR) {choose ERR0 with ⌊ERR0⌋ ∨ ERR0 = ESUCCESS in ERR := ERR0};