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Proof step 7 from proof inv-isbad (previous step)

m < # pebs, mtd-cons(pebs) ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then isbad := pebs[m].bad else isbad := ?⟫ true

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 8:
m < # pebs, mtd-cons(pebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err = ESUCCESS then isbad := pebs[m].bad else isbad := ?⟫ true
Proof step 12:
m < # pebs, mtd-cons(pebs) ⊦ ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 7 from proof inv-isbad (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information