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Proof step 8 from proof inv-isbad (previous step)

m < # pebs, mtd-cons(pebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err = ESUCCESS then isbad := pebs[m].bad else isbad := ?⟫ true

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

Additional information