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Proof step 11 from proof is-encoded-app-one (previous step)

# buf0 = EB_PAGE_SIZE, # buf3 = EB_PAGE_SIZE, is-encoded(rnode(m), buf3), is-encoded(nx0, buf2), is-encoded(rnode(n), buf0), ∀ n, buf. is-encoded(nx0 + n ', buf) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ is-encoded(nx0, buf0) ∧ is-encoded(rnode(n), buf1)) ⊦ ∃ buf, buf4. (buf3 + buf2) + buf0 = buf + buf4 ∧ is-encoded(rnode(m), buf) ∧ is-encoded(nx0 + n ', buf4)

User applied rule all left

And obtained the following new goals

Proof step 12:
# buf3 = EB_PAGE_SIZE, # buf0 = EB_PAGE_SIZE, is-encoded(nx0 + n ', buf2 + buf0) ↔ (∃ buf3, buf1. buf2 + buf0 = buf3 + buf1 ∧ is-encoded(nx0, buf3) ∧ is-encoded(rnode(n), buf1)), is-encoded(rnode(n), buf0), is-encoded(nx0, buf2), is-encoded(rnode(m), buf3) ⊦ ∃ buf, buf4. (buf3 + buf2) + buf0 = buf + buf4 ∧ is-encoded(rnode(m), buf) ∧ is-encoded(nx0 + n ', buf4)

Rule argument

pos: left 6 terms: n, buf2 + buf0 abort: F discard: T computed: F

Additional information

Used terms: n, buf2 + buf0