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Proof step 12 from proof is-encoded-app-one (previous step)

# buf3 = EB_PAGE_SIZE, # buf0 = EB_PAGE_SIZE, is-encoded(nx0 + n ', buf2 + buf0) ↔ (∃ buf3, buf1. buf2 + buf0 = buf3 + buf1 ∧ is-encoded(nx0, buf3) ∧ is-encoded(rnode(n), buf1)), is-encoded(rnode(n), buf0), is-encoded(nx0, buf2), is-encoded(rnode(m), buf3) ⊦ ∃ buf, buf4. (buf3 + buf2) + buf0 = buf + buf4 ∧ is-encoded(rnode(m), buf) ∧ is-encoded(nx0 + n ', buf4)

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 3

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