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Proof step 13 from proof is-encoded-app-one (previous step)

# buf0 = EB_PAGE_SIZE, # buf3 = EB_PAGE_SIZE, is-encoded(rnode(m), buf3), is-encoded(nx0, buf2), is-encoded(rnode(n), buf0) ⊦ is-encoded(nx0 + n ', buf2 + buf0), ∃ buf, buf4. (buf3 + buf2) + buf0 = buf + buf4 ∧ is-encoded(rnode(m), buf) ∧ is-encoded(nx0 + n ', buf4), ∃ buf3, buf1. buf2 + buf0 = buf3 + buf1 ∧ is-encoded(nx0, buf3) ∧ is-encoded(rnode(n), buf1)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: buf2, buf0

Additional information

Used simplifier rules: ⊦ is-encoded(rnd, buf) → (is-encoded(rnd0, buf) ↔ rnd = rnd0); (s) Used terms: buf2, buf0