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Proof step 2 from proof rangeeq-concrete-unfold (previous step)

⊦ range=(avol, n, avol0, n, m) ↔ avol[n] = avol0[n] ∧ range=(avol, n + 1, avol0, n + 1, m - 1), m = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
m = m0 + 1 ⊦ range=(avol, n, avol0, n, m) ↔ avol[n] = avol0[n] ∧ range=(avol, n + 1, avol0, n + 1, m0), m = 0

Rule argument

spec: nat name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [m, m0]

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: m, m0