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Proof step 3 from proof rangeeq-concrete-unfold (previous step)

m = m0 + 1 ⊦ range=(avol, n, avol0, n, m) ↔ avol[n] = avol0[n] ∧ range=(avol, n + 1, avol0, n + 1, m0), m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ range=(avol, n, avol0, n, m0 + 1) ↔ avol[n] = avol0[n] ∧ range=(avol, n + 1, avol0, n + 1, m0)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + 1 ≠ 0; (s)