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Proof step 1 from proof lebs-range-eq (conclusion)

⊦ m ≤ n0 ∧ n0 + n1 ≤ m + m2 ∧ range=(avol0, m, avol1, m, m2) → lebs(avol0, n0, n1) = lebs(avol1, n0, n1)

System applied rule normalize

And obtained the following new goals

Proof step 2:
range=(avol0, m, avol1, m, m2), m ≤ n0, n0 + n1 ≤ m + m2 ⊦ lebs(avol0, n0, n1) = lebs(avol1, n0, n1)

Rule argument

Additional information