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Theorem lebs-range-eq
⊦ m ≤ n0 ∧ n0 + n1 ≤ m + m2 ∧ range=(avol0, m, avol1, m, m2) → lebs(avol0, n0, n1) = lebs(avol1, n0, n1)
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
persistence-io-asm
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 8
Proof steps: 19
Used lemmas:
lebs-rec
,
lebs-base
,
Used spec theorems:
array-splice
/avolume/
range-eq-ext
Used simplifier rules:
nat
/
succ-01
nat-basic
/
succ
nat
/
fle-01
nat
/
lels
nat
/
ls-le-simp
array-splice
/buffer/
append-a
array-splice
/buffer/
append-eq-left
nat
/
lels-03
nat
/
fle
nat
/
sub-add
nat
/
add-01
nat
/
lep
nat-basic
/
a
nat-basic
/
c
nat-basic
/
l
nat-basic
/
f
nat
/
elim-sub