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Proof step 11 from proof inv-flashsize-app (previous step)

# x1 = # lax1, # x0 = # lax0, ∀ n. n < # lax0 → lax0[n].size = x0[n].flashsize, ∀ n. n < # lax1 → lax1[n].size = x1[n].flashsize ⊦ #(x0 + x1) = #(lax0 + lax1) ∧ (∀ n. n < #(x0 + x1) → (lax0 + lax1)[n].size = (x0 + x1)[n].flashsize)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
# x0 = # lax0, # x1 = # lax1, n < # lax0 + # lax1, ∀ n. n < # lax1 → lax1[n].size = x1[n].flashsize, ∀ n. n < # lax0 → lax0[n].size = x0[n].flashsize ⊦ (lax0 + lax1)[n].size = (x0 + x1)[n].flashsize

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ #(lax + lax0) = # lax + # lax0; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ #(x + y) = # x + # y; (s)