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Proof step 9 from proof inv-flashsize-app (previous step)

# x0 = # lax0, # x1 = # lax1, ∀ n. n < # lax1 → lax1[n].size = x1[n].flashsize, ∀ n. n < # lax0 → lax0[n].size = x0[n].flashsize ⊦ inv-flashsize(x0 + x1, lax0 + lax1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ inv-flashsize(x, lax) ↔ # x = # lax ∧ (∀ n. n < # x → lax[n].size = x[n].flashsize)
Proof step 11:
# x1 = # lax1, # x0 = # lax0, ∀ n. n < # lax0 → lax0[n].size = x0[n].flashsize, ∀ n. n < # lax1 → lax1[n].size = x1[n].flashsize ⊦ #(x0 + x1) = #(lax0 + lax1) ∧ (∀ n. n < #(x0 + x1) → (lax0 + lax1)[n].size = (x0 + x1)[n].flashsize)

Rule argument

spec: <toplevel> name: inv-flashsize seq: ⊦ inv-flashsize(x, lax) ↔ # x = # lax ∧ (∀ n. n < # x → lax[n].size = x[n].flashsize) subst: [lax, x] → [lax0 + lax1, x0 + x1] flags: <all paths>

Additional information

Used terms: lax0 + lax1, x0 + x1